Optimal. Leaf size=247 \[ \frac{1}{10} x^5 \left (2 a^2+b^2\right )-\frac{3 \sqrt{\frac{\pi }{2}} a b \sin (c) \text{FresnelC}\left (\sqrt{\frac{2}{\pi }} \sqrt{d} x\right )}{2 d^{5/2}}-\frac{3 \sqrt{\frac{\pi }{2}} a b \cos (c) S\left (\sqrt{d} \sqrt{\frac{2}{\pi }} x\right )}{2 d^{5/2}}+\frac{3 a b x \sin \left (c+d x^2\right )}{2 d^2}-\frac{a b x^3 \cos \left (c+d x^2\right )}{d}+\frac{3 \sqrt{\pi } b^2 \cos (2 c) \text{FresnelC}\left (\frac{2 \sqrt{d} x}{\sqrt{\pi }}\right )}{64 d^{5/2}}-\frac{3 \sqrt{\pi } b^2 \sin (2 c) S\left (\frac{2 \sqrt{d} x}{\sqrt{\pi }}\right )}{64 d^{5/2}}-\frac{3 b^2 x \cos \left (2 c+2 d x^2\right )}{32 d^2}-\frac{b^2 x^3 \sin \left (2 c+2 d x^2\right )}{8 d} \]
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Rubi [A] time = 0.241754, antiderivative size = 247, normalized size of antiderivative = 1., number of steps used = 13, number of rules used = 8, integrand size = 18, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.444, Rules used = {3403, 6, 3386, 3385, 3354, 3352, 3351, 3353} \[ \frac{1}{10} x^5 \left (2 a^2+b^2\right )-\frac{3 \sqrt{\frac{\pi }{2}} a b \sin (c) \text{FresnelC}\left (\sqrt{\frac{2}{\pi }} \sqrt{d} x\right )}{2 d^{5/2}}-\frac{3 \sqrt{\frac{\pi }{2}} a b \cos (c) S\left (\sqrt{d} \sqrt{\frac{2}{\pi }} x\right )}{2 d^{5/2}}+\frac{3 a b x \sin \left (c+d x^2\right )}{2 d^2}-\frac{a b x^3 \cos \left (c+d x^2\right )}{d}+\frac{3 \sqrt{\pi } b^2 \cos (2 c) \text{FresnelC}\left (\frac{2 \sqrt{d} x}{\sqrt{\pi }}\right )}{64 d^{5/2}}-\frac{3 \sqrt{\pi } b^2 \sin (2 c) S\left (\frac{2 \sqrt{d} x}{\sqrt{\pi }}\right )}{64 d^{5/2}}-\frac{3 b^2 x \cos \left (2 c+2 d x^2\right )}{32 d^2}-\frac{b^2 x^3 \sin \left (2 c+2 d x^2\right )}{8 d} \]
Antiderivative was successfully verified.
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Rule 3403
Rule 6
Rule 3386
Rule 3385
Rule 3354
Rule 3352
Rule 3351
Rule 3353
Rubi steps
\begin{align*} \int x^4 \left (a+b \sin \left (c+d x^2\right )\right )^2 \, dx &=\int \left (a^2 x^4+\frac{b^2 x^4}{2}-\frac{1}{2} b^2 x^4 \cos \left (2 c+2 d x^2\right )+2 a b x^4 \sin \left (c+d x^2\right )\right ) \, dx\\ &=\int \left (\left (a^2+\frac{b^2}{2}\right ) x^4-\frac{1}{2} b^2 x^4 \cos \left (2 c+2 d x^2\right )+2 a b x^4 \sin \left (c+d x^2\right )\right ) \, dx\\ &=\frac{1}{10} \left (2 a^2+b^2\right ) x^5+(2 a b) \int x^4 \sin \left (c+d x^2\right ) \, dx-\frac{1}{2} b^2 \int x^4 \cos \left (2 c+2 d x^2\right ) \, dx\\ &=\frac{1}{10} \left (2 a^2+b^2\right ) x^5-\frac{a b x^3 \cos \left (c+d x^2\right )}{d}-\frac{b^2 x^3 \sin \left (2 c+2 d x^2\right )}{8 d}+\frac{(3 a b) \int x^2 \cos \left (c+d x^2\right ) \, dx}{d}+\frac{\left (3 b^2\right ) \int x^2 \sin \left (2 c+2 d x^2\right ) \, dx}{8 d}\\ &=\frac{1}{10} \left (2 a^2+b^2\right ) x^5-\frac{a b x^3 \cos \left (c+d x^2\right )}{d}-\frac{3 b^2 x \cos \left (2 c+2 d x^2\right )}{32 d^2}+\frac{3 a b x \sin \left (c+d x^2\right )}{2 d^2}-\frac{b^2 x^3 \sin \left (2 c+2 d x^2\right )}{8 d}-\frac{(3 a b) \int \sin \left (c+d x^2\right ) \, dx}{2 d^2}+\frac{\left (3 b^2\right ) \int \cos \left (2 c+2 d x^2\right ) \, dx}{32 d^2}\\ &=\frac{1}{10} \left (2 a^2+b^2\right ) x^5-\frac{a b x^3 \cos \left (c+d x^2\right )}{d}-\frac{3 b^2 x \cos \left (2 c+2 d x^2\right )}{32 d^2}+\frac{3 a b x \sin \left (c+d x^2\right )}{2 d^2}-\frac{b^2 x^3 \sin \left (2 c+2 d x^2\right )}{8 d}-\frac{(3 a b \cos (c)) \int \sin \left (d x^2\right ) \, dx}{2 d^2}+\frac{\left (3 b^2 \cos (2 c)\right ) \int \cos \left (2 d x^2\right ) \, dx}{32 d^2}-\frac{(3 a b \sin (c)) \int \cos \left (d x^2\right ) \, dx}{2 d^2}-\frac{\left (3 b^2 \sin (2 c)\right ) \int \sin \left (2 d x^2\right ) \, dx}{32 d^2}\\ &=\frac{1}{10} \left (2 a^2+b^2\right ) x^5-\frac{a b x^3 \cos \left (c+d x^2\right )}{d}-\frac{3 b^2 x \cos \left (2 c+2 d x^2\right )}{32 d^2}+\frac{3 b^2 \sqrt{\pi } \cos (2 c) C\left (\frac{2 \sqrt{d} x}{\sqrt{\pi }}\right )}{64 d^{5/2}}-\frac{3 a b \sqrt{\frac{\pi }{2}} \cos (c) S\left (\sqrt{d} \sqrt{\frac{2}{\pi }} x\right )}{2 d^{5/2}}-\frac{3 a b \sqrt{\frac{\pi }{2}} C\left (\sqrt{d} \sqrt{\frac{2}{\pi }} x\right ) \sin (c)}{2 d^{5/2}}-\frac{3 b^2 \sqrt{\pi } S\left (\frac{2 \sqrt{d} x}{\sqrt{\pi }}\right ) \sin (2 c)}{64 d^{5/2}}+\frac{3 a b x \sin \left (c+d x^2\right )}{2 d^2}-\frac{b^2 x^3 \sin \left (2 c+2 d x^2\right )}{8 d}\\ \end{align*}
Mathematica [A] time = 0.572672, size = 234, normalized size = 0.95 \[ \frac{64 a^2 d^{5/2} x^5-320 a b d^{3/2} x^3 \cos \left (c+d x^2\right )-240 \sqrt{2 \pi } a b \sin (c) \text{FresnelC}\left (\sqrt{\frac{2}{\pi }} \sqrt{d} x\right )-240 \sqrt{2 \pi } a b \cos (c) S\left (\sqrt{d} \sqrt{\frac{2}{\pi }} x\right )+480 a b \sqrt{d} x \sin \left (c+d x^2\right )-40 b^2 d^{3/2} x^3 \sin \left (2 \left (c+d x^2\right )\right )+15 \sqrt{\pi } b^2 \cos (2 c) \text{FresnelC}\left (\frac{2 \sqrt{d} x}{\sqrt{\pi }}\right )-15 \sqrt{\pi } b^2 \sin (2 c) S\left (\frac{2 \sqrt{d} x}{\sqrt{\pi }}\right )-30 b^2 \sqrt{d} x \cos \left (2 \left (c+d x^2\right )\right )+32 b^2 d^{5/2} x^5}{320 d^{5/2}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.016, size = 189, normalized size = 0.8 \begin{align*}{\frac{{x}^{5}{a}^{2}}{5}}+{\frac{{x}^{5}{b}^{2}}{10}}-{\frac{{b}^{2}}{2} \left ({\frac{{x}^{3}\sin \left ( 2\,d{x}^{2}+2\,c \right ) }{4\,d}}-{\frac{3}{4\,d} \left ( -{\frac{x\cos \left ( 2\,d{x}^{2}+2\,c \right ) }{4\,d}}+{\frac{\sqrt{\pi }}{8} \left ( \cos \left ( 2\,c \right ){\it FresnelC} \left ( 2\,{\frac{x\sqrt{d}}{\sqrt{\pi }}} \right ) -\sin \left ( 2\,c \right ){\it FresnelS} \left ( 2\,{\frac{x\sqrt{d}}{\sqrt{\pi }}} \right ) \right ){d}^{-{\frac{3}{2}}}} \right ) } \right ) }+2\,ab \left ( -1/2\,{\frac{{x}^{3}\cos \left ( d{x}^{2}+c \right ) }{d}}+3/2\,{\frac{1}{d} \left ( 1/2\,{\frac{x\sin \left ( d{x}^{2}+c \right ) }{d}}-1/4\,{\frac{\sqrt{2}\sqrt{\pi }}{{d}^{3/2}} \left ( \cos \left ( c \right ){\it FresnelS} \left ({\frac{x\sqrt{d}\sqrt{2}}{\sqrt{\pi }}} \right ) +\sin \left ( c \right ){\it FresnelC} \left ({\frac{x\sqrt{d}\sqrt{2}}{\sqrt{\pi }}} \right ) \right ) } \right ) } \right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [C] time = 1.85333, size = 807, normalized size = 3.27 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.25266, size = 595, normalized size = 2.41 \begin{align*} \frac{32 \,{\left (2 \, a^{2} + b^{2}\right )} d^{3} x^{5} - 320 \, a b d^{2} x^{3} \cos \left (d x^{2} + c\right ) - 60 \, b^{2} d x \cos \left (d x^{2} + c\right )^{2} - 240 \, \sqrt{2} \pi a b \sqrt{\frac{d}{\pi }} \cos \left (c\right ) \operatorname{S}\left (\sqrt{2} x \sqrt{\frac{d}{\pi }}\right ) - 240 \, \sqrt{2} \pi a b \sqrt{\frac{d}{\pi }} \operatorname{C}\left (\sqrt{2} x \sqrt{\frac{d}{\pi }}\right ) \sin \left (c\right ) + 15 \, \pi b^{2} \sqrt{\frac{d}{\pi }} \cos \left (2 \, c\right ) \operatorname{C}\left (2 \, x \sqrt{\frac{d}{\pi }}\right ) - 15 \, \pi b^{2} \sqrt{\frac{d}{\pi }} \operatorname{S}\left (2 \, x \sqrt{\frac{d}{\pi }}\right ) \sin \left (2 \, c\right ) + 30 \, b^{2} d x - 80 \,{\left (b^{2} d^{2} x^{3} \cos \left (d x^{2} + c\right ) - 6 \, a b d x\right )} \sin \left (d x^{2} + c\right )}{320 \, d^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int x^{4} \left (a + b \sin{\left (c + d x^{2} \right )}\right )^{2}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [C] time = 1.42665, size = 444, normalized size = 1.8 \begin{align*} \frac{1}{5} \, a^{2} x^{5} + \frac{1}{10} \, b^{2} x^{5} - \frac{3 i \, \sqrt{2} \sqrt{\pi } a b \operatorname{erf}\left (-\frac{1}{2} \, \sqrt{2} x{\left (-\frac{i \, d}{{\left | d \right |}} + 1\right )} \sqrt{{\left | d \right |}}\right ) e^{\left (i \, c\right )}}{8 \, d^{2}{\left (-\frac{i \, d}{{\left | d \right |}} + 1\right )} \sqrt{{\left | d \right |}}} + \frac{3 i \, \sqrt{2} \sqrt{\pi } a b \operatorname{erf}\left (-\frac{1}{2} \, \sqrt{2} x{\left (\frac{i \, d}{{\left | d \right |}} + 1\right )} \sqrt{{\left | d \right |}}\right ) e^{\left (-i \, c\right )}}{8 \, d^{2}{\left (\frac{i \, d}{{\left | d \right |}} + 1\right )} \sqrt{{\left | d \right |}}} - \frac{3 \, \sqrt{\pi } b^{2} \operatorname{erf}\left (-\sqrt{d} x{\left (-\frac{i \, d}{{\left | d \right |}} + 1\right )}\right ) e^{\left (2 i \, c\right )}}{128 \, d^{\frac{5}{2}}{\left (-\frac{i \, d}{{\left | d \right |}} + 1\right )}} - \frac{3 \, \sqrt{\pi } b^{2} \operatorname{erf}\left (-\sqrt{d} x{\left (\frac{i \, d}{{\left | d \right |}} + 1\right )}\right ) e^{\left (-2 i \, c\right )}}{128 \, d^{\frac{5}{2}}{\left (\frac{i \, d}{{\left | d \right |}} + 1\right )}} - \frac{{\left (-4 i \, b^{2} d x^{3} + 3 \, b^{2} x\right )} e^{\left (2 i \, d x^{2} + 2 i \, c\right )}}{64 \, d^{2}} + \frac{i \,{\left (2 i \, a b d x^{3} - 3 \, a b x\right )} e^{\left (i \, d x^{2} + i \, c\right )}}{4 \, d^{2}} + \frac{i \,{\left (2 i \, a b d x^{3} + 3 \, a b x\right )} e^{\left (-i \, d x^{2} - i \, c\right )}}{4 \, d^{2}} - \frac{{\left (4 i \, b^{2} d x^{3} + 3 \, b^{2} x\right )} e^{\left (-2 i \, d x^{2} - 2 i \, c\right )}}{64 \, d^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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